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5(x-4)=2(2x-5)
We move all terms to the left:
5(x-4)-(2(2x-5))=0
We multiply parentheses
5x-(2(2x-5))-20=0
We calculate terms in parentheses: -(2(2x-5)), so:We get rid of parentheses
2(2x-5)
We multiply parentheses
4x-10
Back to the equation:
-(4x-10)
5x-4x+10-20=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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