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(2x)+(x+12)+(96)=190
We move all terms to the left:
(2x)+(x+12)+(96)-(190)=0
We add all the numbers together, and all the variables
2x+(x+12)-94=0
We get rid of parentheses
2x+x+12-94=0
We add all the numbers together, and all the variables
3x-82=0
We move all terms containing x to the left, all other terms to the right
3x=82
x=82/3
x=27+1/3
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