5(x-4)-(3x-1)=3(2x-3)+6

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Solution for 5(x-4)-(3x-1)=3(2x-3)+6 equation: 



5(x-4)-(3x-1)=3(2x-3)+6

We move all terms to the left:

5(x-4)-(3x-1)-(3(2x-3)+6)=0

We multiply parentheses

5x-(3x-1)-(3(2x-3)+6)-20=0

We get rid of parentheses

5x-3x-(3(2x-3)+6)+1-20=0



We calculate terms in parentheses: -(3(2x-3)+6), so:

3(2x-3)+6

We multiply parentheses

6x-9+6

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

2x-(6x-3)-19=0

We get rid of parentheses

2x-6x+3-19=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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