(x)(x+14)(7)=1925

Solution for (x)(x+14)(7)=1925 equation:

(x)(x+14)(7)=1925

We move all terms to the left:

(x)(x+14)(7)-(1925)=0

We multiply parentheses

7x^2+98x-1925=0

a = 7; b = 98; c = -1925;
Δ = b2-4ac
Δ = 982-4·7·(-1925)
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{63504}=252$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-252}{2*7}=\frac{-350}{14}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+252}{2*7}=\frac{154}{14}
=11
$