5(x-4)+20=1+12x-21

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Solution for 5(x-4)+20=1+12x-21 equation: 



5(x-4)+20=1+12x-21

We move all terms to the left:

5(x-4)+20-(1+12x-21)=0

We add all the numbers together, and all the variables

5(x-4)-(12x-20)+20=0

We multiply parentheses

5x-(12x-20)-20+20=0

We get rid of parentheses

5x-12x+20-20+20=0

We add all the numbers together, and all the variables

-7x+20=0

We move all terms containing x to the left, all other terms to the right

-7x=-20

x=-20/-7

x=2+6/7

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