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5(x-4)+8x=1+12x-21
We move all terms to the left:
5(x-4)+8x-(1+12x-21)=0
We add all the numbers together, and all the variables
5(x-4)+8x-(12x-20)=0
We add all the numbers together, and all the variables
8x+5(x-4)-(12x-20)=0
We multiply parentheses
8x+5x-(12x-20)-20=0
We get rid of parentheses
8x+5x-12x+20-20=0
We add all the numbers together, and all the variables
x=0
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