5(x-3)=6(x-2)-(x+3)

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Solution for 5(x-3)=6(x-2)-(x+3) equation: 



5(x-3)=6(x-2)-(x+3)

We move all terms to the left:

5(x-3)-(6(x-2)-(x+3))=0

We multiply parentheses

5x-(6(x-2)-(x+3))-15=0



We calculate terms in parentheses: -(6(x-2)-(x+3)), so:

6(x-2)-(x+3)

We multiply parentheses

6x-(x+3)-12

We get rid of parentheses

6x-x-3-12

We add all the numbers together, and all the variables

5x-15

Back to the equation:

-(5x-15)



We get rid of parentheses

5x-5x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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