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4x+8/6x-5=33
We move all terms to the left:
4x+8/6x-5-(33)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
4x+8/6x-38=0
We multiply all the terms by the denominator
4x*6x-38*6x+8=0
Wy multiply elements
24x^2-228x+8=0
a = 24; b = -228; c = +8;
Δ = b2-4ac
Δ = -2282-4·24·8
Δ = 51216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{51216}=\sqrt{16*3201}=\sqrt{16}*\sqrt{3201}=4\sqrt{3201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-228)-4\sqrt{3201}}{2*24}=\frac{228-4\sqrt{3201}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-228)+4\sqrt{3201}}{2*24}=\frac{228+4\sqrt{3201}}{48} $
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