(3x+50)=(x+12)

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Solution for (3x+50)=(x+12) equation: 



(3x+50)=(x+12)

We move all terms to the left:

(3x+50)-((x+12))=0

We get rid of parentheses

3x-((x+12))+50=0



We calculate terms in parentheses: -((x+12)), so:

(x+12)

We get rid of parentheses

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

3x-x-12+50=0

We add all the numbers together, and all the variables

2x+38=0

We move all terms containing x to the left, all other terms to the right

2x=-38

x=-38/2

x=-19

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