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5(x-3)=4(x+10)
We move all terms to the left:
5(x-3)-(4(x+10))=0
We multiply parentheses
5x-(4(x+10))-15=0
We calculate terms in parentheses: -(4(x+10)), so:We get rid of parentheses
4(x+10)
We multiply parentheses
4x+40
Back to the equation:
-(4x+40)
5x-4x-40-15=0
We add all the numbers together, and all the variables
x-55=0
We move all terms containing x to the left, all other terms to the right
x=55
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