If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2-9x-13=0
a = 5; b = -9; c = -13;
Δ = b2-4ac
Δ = -92-4·5·(-13)
Δ = 341
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{341}}{2*5}=\frac{9-\sqrt{341}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{341}}{2*5}=\frac{9+\sqrt{341}}{10} $
| X÷2-1÷3=x÷5+1÷4 | | 5x–12=2x+6 | | 9+w=54 | | 5n-3=5-3n | | 9+w=-54 | | 5n+3=5+3n | | 3x+5=6x-40=180 | | d÷5=10 | | 3x+1=x–1 | | x+15=–49 | | (x-0.75)(x-1.5)(x-3)=0 | | 15x−8 =14x+13 | | 14+6x=76 | | 10(s-8)=-140 | | 3x+5+6x-40=180 | | -5+r=r-8 | | 3x-12=1/2(6x-6) | | 8b=-6b-2b | | -7+f=-12 | | 3x/2=-33 | | 4(2y+1)=3(y-2) | | 16s+40=168 | | 7(p-2-2)(7-3p)+2=0 | | 9(x-6)=28 | | 10l+45=75 | | 2x-4/3x+2=-2/3 | | 15x+4=26 | | 3(4x-3)=4x+12 | | 6.2+x=14 | | -2(s+2)=-4 | | t/3-17=-15 | | 48x2-84x+36=0 |