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5(x-3)=2(5-x)
We move all terms to the left:
5(x-3)-(2(5-x))=0
We add all the numbers together, and all the variables
5(x-3)-(2(-1x+5))=0
We multiply parentheses
5x-(2(-1x+5))-15=0
We calculate terms in parentheses: -(2(-1x+5)), so:We get rid of parentheses
2(-1x+5)
We multiply parentheses
-2x+10
Back to the equation:
-(-2x+10)
5x+2x-10-15=0
We add all the numbers together, and all the variables
7x-25=0
We move all terms containing x to the left, all other terms to the right
7x=25
x=25/7
x=3+4/7
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