3(b-8)=4(+10b)=66

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Solution for 3(b-8)=4(+10b)=66 equation: 



3(b-8)=4(+10b)=66

We move all terms to the left:

3(b-8)-(4(+10b))=0

We multiply parentheses

3b-(4(+10b))-24=0



We calculate terms in parentheses: -(4(+10b)), so:

4(+10b)

We multiply parentheses

40b

Back to the equation:

-(40b)



We add all the numbers together, and all the variables

-37b-24=0

We move all terms containing b to the left, all other terms to the right

-37b=24

b=24/-37

b=-24/37

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