5(x-3)-(2/5)(5x-10)=-(1/2)(6-8x)

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Solution for 5(x-3)-(2/5)(5x-10)=-(1/2)(6-8x) equation: 



5(x-3)-(2/5)(5x-10)=-(1/2)(6-8x)

We move all terms to the left:

5(x-3)-(2/5)(5x-10)-(-(1/2)(6-8x))=0



Domain of the equation: 5)(5x-10)!=0

x∈R





Domain of the equation: 2)(6-8x))!=0

x∈R



We add all the numbers together, and all the variables

5(x-3)-(+2/5)(5x-10)-(-(+1/2)(-8x+6))=0

We multiply parentheses

5x-(+2/5)(5x-10)-(-(+1/2)(-8x+6))-15=0

We multiply parentheses ..

-(+10x^2+2/5*-10)+5x-(-(+1/2)(-8x+6))-15=0

We calculate fractions


(-(+10x^2+2*2)(-8x+6)))/(+5x-10)*2)(-8x+6))+5*)+()/(-10)*2)(-8x+6))+5*)-15=0

We add all the numbers together, and all the variables

(-(+10x^2+2*2)(-8x+6)))/(5x-10)*2)(-8x+6))+5*)+()/(-10)*2)(-8x+6))+5*)-15=0

We calculate fractions


((-(+10x^2+2*2)(-8x+6)))*(-10)*2)(-8x+6))+5*)-15)/((5x*(-10)*2)(-8x+6))+5*)-15)+(-10)*2)(-8x+6))+5*)+()*5x/((5x*(-10)*2)(-8x+6))+5*)-15)=0

We can not solve this equation

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