1/7(3x-2)=1/7+2x+1

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Solution for 1/7(3x-2)=1/7+2x+1 equation: 



1/7(3x-2)=1/7+2x+1

We move all terms to the left:

1/7(3x-2)-(1/7+2x+1)=0



Domain of the equation: 7(3x-2)!=0

x∈R





Domain of the equation: 7+2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x+1)!=-7

x∈R



We add all the numbers together, and all the variables

1/7(3x-2)-(2x+1/7+1)=0

We get rid of parentheses

1/7(3x-2)-2x-1-1/7=0

We calculate fractions


-2x-1=0

We move all terms containing x to the left, all other terms to the right

-2x=1

x=1/-2

x=-1/2

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