5(x-3)+x=6(x-4)+9

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Solution for 5(x-3)+x=6(x-4)+9 equation: 



5(x-3)+x=6(x-4)+9

We move all terms to the left:

5(x-3)+x-(6(x-4)+9)=0

We add all the numbers together, and all the variables

x+5(x-3)-(6(x-4)+9)=0

We multiply parentheses

x+5x-(6(x-4)+9)-15=0



We calculate terms in parentheses: -(6(x-4)+9), so:

6(x-4)+9

We multiply parentheses

6x-24+9

We add all the numbers together, and all the variables

6x-15

Back to the equation:

-(6x-15)



We add all the numbers together, and all the variables

6x-(6x-15)-15=0

We get rid of parentheses

6x-6x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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