3c+c+(3c-20)=400

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Solution for 3c+c+(3c-20)=400 equation: 



3c+c+(3c-20)=400

We move all terms to the left:

3c+c+(3c-20)-(400)=0

We add all the numbers together, and all the variables

4c+(3c-20)-400=0

We get rid of parentheses

4c+3c-20-400=0

We add all the numbers together, and all the variables

7c-420=0

We move all terms containing c to the left, all other terms to the right

7c=420

c=420/7

c=60

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