5(x-3)+8x=6(2x-4)

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Solution for 5(x-3)+8x=6(2x-4) equation: 



5(x-3)+8x=6(2x-4)

We move all terms to the left:

5(x-3)+8x-(6(2x-4))=0

We add all the numbers together, and all the variables

8x+5(x-3)-(6(2x-4))=0

We multiply parentheses

8x+5x-(6(2x-4))-15=0



We calculate terms in parentheses: -(6(2x-4)), so:

6(2x-4)

We multiply parentheses

12x-24

Back to the equation:

-(12x-24)



We add all the numbers together, and all the variables

13x-(12x-24)-15=0

We get rid of parentheses

13x-12x+24-15=0

We add all the numbers together, and all the variables

x+9=0

We move all terms containing x to the left, all other terms to the right

x=-9

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