5(x-3)+6=10-2(3x+4)

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Solution for 5(x-3)+6=10-2(3x+4) equation: 



5(x-3)+6=10-2(3x+4)

We move all terms to the left:

5(x-3)+6-(10-2(3x+4))=0

We multiply parentheses

5x-(10-2(3x+4))-15+6=0



We calculate terms in parentheses: -(10-2(3x+4)), so:

10-2(3x+4)

determiningTheFunctionDomain
-2(3x+4)+10

We multiply parentheses

-6x-8+10

We add all the numbers together, and all the variables

-6x+2

Back to the equation:

-(-6x+2)



We add all the numbers together, and all the variables

5x-(-6x+2)-9=0

We get rid of parentheses

5x+6x-2-9=0

We add all the numbers together, and all the variables

11x-11=0

We move all terms containing x to the left, all other terms to the right

11x=11

x=11/11

x=1

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