-6(3f-7)=-26+4f

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Solution for -6(3f-7)=-26+4f equation: 



-6(3f-7)=-26+4f

We move all terms to the left:

-6(3f-7)-(-26+4f)=0

We add all the numbers together, and all the variables

-6(3f-7)-(4f-26)=0

We multiply parentheses

-18f-(4f-26)+42=0

We get rid of parentheses

-18f-4f+26+42=0

We add all the numbers together, and all the variables

-22f+68=0

We move all terms containing f to the left, all other terms to the right

-22f=-68

f=-68/-22

f=3+1/11

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