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5(x-3)+11x=(5x-1)
We move all terms to the left:
5(x-3)+11x-((5x-1))=0
We add all the numbers together, and all the variables
11x+5(x-3)-((5x-1))=0
We multiply parentheses
11x+5x-((5x-1))-15=0
We calculate terms in parentheses: -((5x-1)), so:We add all the numbers together, and all the variables
(5x-1)
We get rid of parentheses
5x-1
Back to the equation:
-(5x-1)
16x-(5x-1)-15=0
We get rid of parentheses
16x-5x+1-15=0
We add all the numbers together, and all the variables
11x-14=0
We move all terms containing x to the left, all other terms to the right
11x=14
x=14/11
x=1+3/11
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