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5(x-3)+(2x=4)
We move all terms to the left:
5(x-3)+(2x-(4))=0
We multiply parentheses
5x+(2x-4)-15=0
We get rid of parentheses
5x+2x-4-15=0
We add all the numbers together, and all the variables
7x-19=0
We move all terms containing x to the left, all other terms to the right
7x=19
x=19/7
x=2+5/7
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