2(x+5)=4(-3+1/4x)

Solution for 2(x+5)=4(-3+1/4x) equation:

2(x+5)=4(-3+1/4x)

We move all terms to the left:

2(x+5)-(4(-3+1/4x))=0


Domain of the equation: 4x))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2(x+5)-(4(1/4x-3))=0

We multiply parentheses

2x-(4(1/4x-3))+10=0

We multiply all the terms by the denominator


2x*4x+10*4x-3))-(4(1-3))=0

We add all the numbers together, and all the variables

2x*4x+10*4x-3))-(4(-2))=0

We add all the numbers together, and all the variables

2x*4x+10*4x=0

Wy multiply elements

8x^2+40x=0

a = 8; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·8·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*8}=\frac{-80}{16}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*8}=\frac{0}{16}
=0
$