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5(x-2)-3(1-2x)=4(x+2)
We move all terms to the left:
5(x-2)-3(1-2x)-(4(x+2))=0
We add all the numbers together, and all the variables
5(x-2)-3(-2x+1)-(4(x+2))=0
We multiply parentheses
5x+6x-(4(x+2))-10-3=0
We calculate terms in parentheses: -(4(x+2)), so:We add all the numbers together, and all the variables
4(x+2)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
11x-(4x+8)-13=0
We get rid of parentheses
11x-4x-8-13=0
We add all the numbers together, and all the variables
7x-21=0
We move all terms containing x to the left, all other terms to the right
7x=21
x=21/7
x=3
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