(3x+7/x+1)+(4x-11/2x+3)=5

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Solution for (3x+7/x+1)+(4x-11/2x+3)=5 equation: 



(3x+7/x+1)+(4x-11/2x+3)=5

We move all terms to the left:

(3x+7/x+1)+(4x-11/2x+3)-(5)=0



Domain of the equation: x+1)!=0

x∈R





Domain of the equation: 2x+3)!=0

x∈R



We get rid of parentheses

3x+7/x+4x-11/2x+1+3-5=0

We calculate fractions


3x+4x+14x/2x^2+(-11x)/2x^2+1+3-5=0

We add all the numbers together, and all the variables

7x+14x/2x^2+(-11x)/2x^2-1=0

We multiply all the terms by the denominator


7x*2x^2+14x+(-11x)-1*2x^2=0

We add all the numbers together, and all the variables

14x+7x*2x^2+(-11x)-1*2x^2=0

Wy multiply elements

14x^3-2x^2+14x+(-11x)=0

We get rid of parentheses

14x^3-2x^2+14x-11x=0

We do not support expression: x^3

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