5(x-2)+x=5(2-x)+4x

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Solution for 5(x-2)+x=5(2-x)+4x equation: 



5(x-2)+x=5(2-x)+4x

We move all terms to the left:

5(x-2)+x-(5(2-x)+4x)=0

We add all the numbers together, and all the variables

5(x-2)+x-(5(-1x+2)+4x)=0

We add all the numbers together, and all the variables

x+5(x-2)-(5(-1x+2)+4x)=0

We multiply parentheses

x+5x-(5(-1x+2)+4x)-10=0



We calculate terms in parentheses: -(5(-1x+2)+4x), so:

5(-1x+2)+4x

We add all the numbers together, and all the variables

4x+5(-1x+2)

We multiply parentheses

4x-5x+10

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

6x-(-1x+10)-10=0

We get rid of parentheses

6x+1x-10-10=0

We add all the numbers together, and all the variables

7x-20=0

We move all terms containing x to the left, all other terms to the right

7x=20

x=20/7

x=2+6/7

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