9(x-2)/6=3(x+9)/13

Solution for 9(x-2)/6=3(x+9)/13 equation:

9(x-2)/6=3(x+9)/13

We move all terms to the left:

9(x-2)/6-(3(x+9)/13)=0

We calculate fractions


9x/()+(-(3(x+9)*6)/()=0


We calculate terms in parentheses: +(-(3(x+9)*6)/(), so:

-(3(x+9)*6)/(

We multiply all the terms by the denominator


-(3(x+9)*6)


We calculate terms in parentheses: -(3(x+9)*6), so:

3(x+9)*6

We multiply parentheses

18x+162

Back to the equation:

-(18x+162)


We get rid of parentheses

-18x-162

Back to the equation:

+(-18x-162)


We get rid of parentheses

9x/()-18x-162=0

We multiply all the terms by the denominator


9x-18x*()-162*()=0

We add all the numbers together, and all the variables

9x-18x*()=0