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5(x-2)+6=3(x-12)
We move all terms to the left:
5(x-2)+6-(3(x-12))=0
We multiply parentheses
5x-(3(x-12))-10+6=0
We calculate terms in parentheses: -(3(x-12)), so:We add all the numbers together, and all the variables
3(x-12)
We multiply parentheses
3x-36
Back to the equation:
-(3x-36)
5x-(3x-36)-4=0
We get rid of parentheses
5x-3x+36-4=0
We add all the numbers together, and all the variables
2x+32=0
We move all terms containing x to the left, all other terms to the right
2x=-32
x=-32/2
x=-16
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