2(x+2)(x+2)-8=72

Solution for 2(x+2)(x+2)-8=72 equation:

2(x+2)(x+2)-8=72

We move all terms to the left:

2(x+2)(x+2)-8-(72)=0

We add all the numbers together, and all the variables

2(x+2)(x+2)-80=0

We multiply parentheses ..

2(+x^2+2x+2x+4)-80=0

We multiply parentheses

2x^2+4x+4x+8-80=0

We add all the numbers together, and all the variables

2x^2+8x-72=0

a = 2; b = 8; c = -72;
Δ = b2-4ac
Δ = 82-4·2·(-72)
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{10}}{2*2}=\frac{-8-8\sqrt{10}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{10}}{2*2}=\frac{-8+8\sqrt{10}}{4}
$