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5(x-2)+20=4(x-+4)
We move all terms to the left:
5(x-2)+20-(4(x-+4))=0
We add all the numbers together, and all the variables
5(x-2)-(4(+x))+20=0
We multiply parentheses
5x-(4(+x))-10+20=0
We calculate terms in parentheses: -(4(+x)), so:We add all the numbers together, and all the variables
4(+x)
We multiply parentheses
4x
Back to the equation:
-(4x)
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10
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