5(2x+4)+6(x-4)+3(x+8)=2x+(1+x)+19

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Solution for 5(2x+4)+6(x-4)+3(x+8)=2x+(1+x)+19 equation: 



5(2x+4)+6(x-4)+3(x+8)=2x+(1+x)+19

We move all terms to the left:

5(2x+4)+6(x-4)+3(x+8)-(2x+(1+x)+19)=0

We add all the numbers together, and all the variables

5(2x+4)+6(x-4)+3(x+8)-(2x+(x+1)+19)=0

We multiply parentheses

10x+6x+3x-(2x+(x+1)+19)+20-24+24=0



We calculate terms in parentheses: -(2x+(x+1)+19), so:

2x+(x+1)+19

We get rid of parentheses

2x+x+1+19

We add all the numbers together, and all the variables

3x+20

Back to the equation:

-(3x+20)



We add all the numbers together, and all the variables

19x-(3x+20)+20=0

We get rid of parentheses

19x-3x-20+20=0

We add all the numbers together, and all the variables

16x=0

x=0/16

x=0

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