5(x-2)+2(1-3x)-(7x+12)=0

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Solution for 5(x-2)+2(1-3x)-(7x+12)=0 equation: 



5(x-2)+2(1-3x)-(7x+12)=0

We add all the numbers together, and all the variables

5(x-2)+2(-3x+1)-(7x+12)=0

We multiply parentheses

5x-6x-(7x+12)-10+2=0

We get rid of parentheses

5x-6x-7x-12-10+2=0

We add all the numbers together, and all the variables

-8x-20=0

We move all terms containing x to the left, all other terms to the right

-8x=20

x=20/-8

x=-2+1/2

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