6(2y+4)=5

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Solution for 6(2y+4)=5 equation: 



6(2y+4)=5

We move all terms to the left:

6(2y+4)-(5)=0

We multiply parentheses

12y+24-5=0

We add all the numbers together, and all the variables

12y+19=0

We move all terms containing y to the left, all other terms to the right

12y=-19

y=-19/12

y=-1+7/12

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