5(x-2)+(-4)=-7(1-x)

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Solution for 5(x-2)+(-4)=-7(1-x) equation: 



5(x-2)+(-4)=-7(1-x)

We move all terms to the left:

5(x-2)+(-4)-(-7(1-x))=0

We add all the numbers together, and all the variables

5(x-2)-(-7(-1x+1))+(-4)=0

We add all the numbers together, and all the variables

5(x-2)-(-7(-1x+1))-4=0

We multiply parentheses

5x-(-7(-1x+1))-10-4=0



We calculate terms in parentheses: -(-7(-1x+1)), so:

-7(-1x+1)

We multiply parentheses

7x-7

Back to the equation:

-(7x-7)



We add all the numbers together, and all the variables

5x-(7x-7)-14=0

We get rid of parentheses

5x-7x+7-14=0

We add all the numbers together, and all the variables

-2x-7=0

We move all terms containing x to the left, all other terms to the right

-2x=7

x=7/-2

x=-3+1/2

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