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5(x-1)-11=2(x+1)+12
We move all terms to the left:
5(x-1)-11-(2(x+1)+12)=0
We multiply parentheses
5x-(2(x+1)+12)-5-11=0
We calculate terms in parentheses: -(2(x+1)+12), so:We add all the numbers together, and all the variables
2(x+1)+12
We multiply parentheses
2x+2+12
We add all the numbers together, and all the variables
2x+14
Back to the equation:
-(2x+14)
5x-(2x+14)-16=0
We get rid of parentheses
5x-2x-14-16=0
We add all the numbers together, and all the variables
3x-30=0
We move all terms containing x to the left, all other terms to the right
3x=30
x=30/3
x=10
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