4y+16=2(4y-2)

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Solution for 4y+16=2(4y-2) equation: 



4y+16=2(4y-2)

We move all terms to the left:

4y+16-(2(4y-2))=0



We calculate terms in parentheses: -(2(4y-2)), so:

2(4y-2)

We multiply parentheses

8y-4

Back to the equation:

-(8y-4)



We get rid of parentheses

4y-8y+4+16=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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