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5(x-1)-(5x+2)=2(3x-3)+11
We move all terms to the left:
5(x-1)-(5x+2)-(2(3x-3)+11)=0
We multiply parentheses
5x-(5x+2)-(2(3x-3)+11)-5=0
We get rid of parentheses
5x-5x-(2(3x-3)+11)-2-5=0
We calculate terms in parentheses: -(2(3x-3)+11), so:We add all the numbers together, and all the variables
2(3x-3)+11
We multiply parentheses
6x-6+11
We add all the numbers together, and all the variables
6x+5
Back to the equation:
-(6x+5)
-(6x+5)-7=0
We get rid of parentheses
-6x-5-7=0
We add all the numbers together, and all the variables
-6x-12=0
We move all terms containing x to the left, all other terms to the right
-6x=12
x=12/-6
x=-2
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