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3-2/5(25-10x)=3/7(14x-21)
We move all terms to the left:
3-2/5(25-10x)-(3/7(14x-21))=0
Domain of the equation: 5(25-10x)!=0
x∈R
Domain of the equation: 7(14x-21))!=0We add all the numbers together, and all the variables
x∈R
-2/5(-10x+25)-(3/7(14x-21))+3=0
We calculate fractions
(-14x1/(5(-10x+25)*7(14x-21)))+(-15x0/(5(-10x+25)*7(14x-21)))+3=0
We calculate terms in parentheses: +(-14x1/(5(-10x+25)*7(14x-21))), so:
-14x1/(5(-10x+25)*7(14x-21))
We multiply all the terms by the denominator
-14x1
We add all the numbers together, and all the variables
-14x
Back to the equation:
+(-14x)
We calculate terms in parentheses: +(-15x0/(5(-10x+25)*7(14x-21))), so:We get rid of parentheses
-15x0/(5(-10x+25)*7(14x-21))
We multiply all the terms by the denominator
-15x0
We add all the numbers together, and all the variables
-15x
Back to the equation:
+(-15x)
-14x-15x+3=0
We add all the numbers together, and all the variables
-29x+3=0
We move all terms containing x to the left, all other terms to the right
-29x=-3
x=-3/-29
x=3/29
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