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5/6c+2/3c=1/3
We move all terms to the left:
5/6c+2/3c-(1/3)=0
Domain of the equation: 6c!=0
c!=0/6
c!=0
c∈R
Domain of the equation: 3c!=0We add all the numbers together, and all the variables
c!=0/3
c!=0
c∈R
5/6c+2/3c-(+1/3)=0
We get rid of parentheses
5/6c+2/3c-1/3=0
We calculate fractions
135c/162c^2+12c/162c^2+(-6c)/162c^2=0
We multiply all the terms by the denominator
135c+12c+(-6c)=0
We add all the numbers together, and all the variables
147c+(-6c)=0
We get rid of parentheses
147c-6c=0
We add all the numbers together, and all the variables
141c=0
c=0/141
c=0
Równanie nie ma rozwiązania
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