5(x-1)+4=6(x+2)-20

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Solution for 5(x-1)+4=6(x+2)-20 equation: 



5(x-1)+4=6(x+2)-20

We move all terms to the left:

5(x-1)+4-(6(x+2)-20)=0

We multiply parentheses

5x-(6(x+2)-20)-5+4=0



We calculate terms in parentheses: -(6(x+2)-20), so:

6(x+2)-20

We multiply parentheses

6x+12-20

We add all the numbers together, and all the variables

6x-8

Back to the equation:

-(6x-8)



We add all the numbers together, and all the variables

5x-(6x-8)-1=0

We get rid of parentheses

5x-6x+8-1=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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