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5(x+4)+2(3x-2)=2(3)
We move all terms to the left:
5(x+4)+2(3x-2)-(2(3))=0
determiningTheFunctionDomain 5(x+4)+2(3x-2)-23=0
We multiply parentheses
5x+6x+20-4-23=0
We add all the numbers together, and all the variables
11x-7=0
We move all terms containing x to the left, all other terms to the right
11x=7
x=7/11
x=7/11
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