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X+5(3/2X-5)=X+5(2/X+5)
We move all terms to the left:
X+5(3/2X-5)-(X+5(2/X+5))=0
Domain of the equation: 2X-5)!=0
X∈R
Domain of the equation: X+5))!=0We multiply parentheses
X∈R
X+15X-(X+5(2/X+5))-25=0
We multiply all the terms by the denominator
X*X+5))+15X*X+5))-(X+5(2-25*X+5))=0
We add all the numbers together, and all the variables
X*X+5))+15X*X+5))-(X+5(-25X+7))=0
Wy multiply elements
X^2+5))+15X*X+5))-(X+5(-25X+7))=0
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