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5(x+3)=2(2x-1)+15
We move all terms to the left:
5(x+3)-(2(2x-1)+15)=0
We multiply parentheses
5x-(2(2x-1)+15)+15=0
We calculate terms in parentheses: -(2(2x-1)+15), so:We get rid of parentheses
2(2x-1)+15
We multiply parentheses
4x-2+15
We add all the numbers together, and all the variables
4x+13
Back to the equation:
-(4x+13)
5x-4x-13+15=0
We add all the numbers together, and all the variables
x+2=0
We move all terms containing x to the left, all other terms to the right
x=-2
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