5(x+2)=6+3(2x+1)

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Solution for 5(x+2)=6+3(2x+1) equation: 



5(x+2)=6+3(2x+1)

We move all terms to the left:

5(x+2)-(6+3(2x+1))=0

We multiply parentheses

5x-(6+3(2x+1))+10=0



We calculate terms in parentheses: -(6+3(2x+1)), so:

6+3(2x+1)

determiningTheFunctionDomain
3(2x+1)+6

We multiply parentheses

6x+3+6

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We get rid of parentheses

5x-6x-9+10=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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