5(x+2)-4=13-7(x+1)

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Solution for 5(x+2)-4=13-7(x+1) equation: 



5(x+2)-4=13-7(x+1)

We move all terms to the left:

5(x+2)-4-(13-7(x+1))=0

We multiply parentheses

5x-(13-7(x+1))+10-4=0



We calculate terms in parentheses: -(13-7(x+1)), so:

13-7(x+1)

determiningTheFunctionDomain
-7(x+1)+13

We multiply parentheses

-7x-7+13

We add all the numbers together, and all the variables

-7x+6

Back to the equation:

-(-7x+6)



We add all the numbers together, and all the variables

5x-(-7x+6)+6=0

We get rid of parentheses

5x+7x-6+6=0

We add all the numbers together, and all the variables

12x=0

x=0/12

x=0

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