2(x-30)+(-x+40)=4(x-50)=

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Solution for 2(x-30)+(-x+40)=4(x-50)= equation: 



2(x-30)+(-x+40)=4(x-50)=

We move all terms to the left:

2(x-30)+(-x+40)-(4(x-50))=0

We add all the numbers together, and all the variables

2(x-30)+(-1x+40)-(4(x-50))=0

We multiply parentheses

2x+(-1x+40)-(4(x-50))-60=0

We get rid of parentheses

2x-1x-(4(x-50))+40-60=0



We calculate terms in parentheses: -(4(x-50)), so:

4(x-50)

We multiply parentheses

4x-200

Back to the equation:

-(4x-200)



We add all the numbers together, and all the variables

x-(4x-200)-20=0

We get rid of parentheses

x-4x+200-20=0

We add all the numbers together, and all the variables

-3x+180=0

We move all terms containing x to the left, all other terms to the right

-3x=-180

x=-180/-3

x=+60

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