5(x+2)+4=8x+1-3(x-5)

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Solution for 5(x+2)+4=8x+1-3(x-5) equation: 



5(x+2)+4=8x+1-3(x-5)

We move all terms to the left:

5(x+2)+4-(8x+1-3(x-5))=0

We multiply parentheses

5x-(8x+1-3(x-5))+10+4=0



We calculate terms in parentheses: -(8x+1-3(x-5)), so:

8x+1-3(x-5)

determiningTheFunctionDomain
8x-3(x-5)+1

We multiply parentheses

8x-3x+15+1

We add all the numbers together, and all the variables

5x+16

Back to the equation:

-(5x+16)



We add all the numbers together, and all the variables

5x-(5x+16)+14=0

We get rid of parentheses

5x-5x-16+14=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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