5(x-2)+x=(x+3)-4

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Solution for 5(x-2)+x=(x+3)-4 equation: 



5(x-2)+x=(x+3)-4

We move all terms to the left:

5(x-2)+x-((x+3)-4)=0

We add all the numbers together, and all the variables

x+5(x-2)-((x+3)-4)=0

We multiply parentheses

x+5x-((x+3)-4)-10=0



We calculate terms in parentheses: -((x+3)-4), so:

(x+3)-4

We get rid of parentheses

x+3-4

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)



We add all the numbers together, and all the variables

6x-(x-1)-10=0

We get rid of parentheses

6x-x+1-10=0

We add all the numbers together, and all the variables

5x-9=0

We move all terms containing x to the left, all other terms to the right

5x=9

x=9/5

x=1+4/5

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