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5(x+10)(x-10)=75x
We move all terms to the left:
5(x+10)(x-10)-(75x)=0
We add all the numbers together, and all the variables
-75x+5(x+10)(x-10)=0
We use the square of the difference formula
x^2-75x-100=0
a = 1; b = -75; c = -100;
Δ = b2-4ac
Δ = -752-4·1·(-100)
Δ = 6025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6025}=\sqrt{25*241}=\sqrt{25}*\sqrt{241}=5\sqrt{241}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-5\sqrt{241}}{2*1}=\frac{75-5\sqrt{241}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+5\sqrt{241}}{2*1}=\frac{75+5\sqrt{241}}{2} $
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