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12x(-12x+420)=0
We multiply parentheses
-144x^2+5040x=0
a = -144; b = 5040; c = 0;
Δ = b2-4ac
Δ = 50402-4·(-144)·0
Δ = 25401600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25401600}=5040$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5040)-5040}{2*-144}=\frac{-10080}{-288} =+35 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5040)+5040}{2*-144}=\frac{0}{-288} =0 $
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